Question

Three coins are tossed simultaneously 200 times with the following frequencies of
different outcomes given in the table. Read the data given in the table carefully.
Outcome 3 tails 2 tails 1 tail no tail
Frequency 20 68 82 30

Answer 1

Question:

Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes . outcome 3 tails , 2 tail, 1 tail, no tail frequency, 20 , 68 , 82 , 30 respectively. if the three coins are tossed again simultaneously compute the probability of getting less than three tails.

Answer:

Given:  

Number of times the coins were tossed = 200  

Frequency of getting 3 tails = 20  

Frequency of getting 2 tails = 68  

Frequency of getting 1 tail = 82  

Frequency of getting no tail = 30

 

To find:  

The probability of getting less than three tails when the three coins are tossed again.

Solution:  

Probability of getting no tail = 30/200  

Probability of getting 1 tail = 82/200  

Probability of getting 2 tails = 68/200  

The probability of getting less than 3 tails = probability of getting 0 tail + 1 tail + 2 tail  

= 30/200 + 82/200+ 68/200  

=180/200  

=9/10  

Therefore the probability of getting less than three tails is 9/10.

Hope this helps you

Answer 2

Answer:

It is given that coin is tossed 200 times Total number of trials = 200

Number of events for getting less than three tails = 68 + 82 + 30 = 180

Probability of getting less than 3 tails =180 / 200 =9 / 10

therefore the Probability of getting less than 3 tails =180 / 200 =9 / 10