three coins are tossed simultaneously find the probability of getting at most two heads
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Answer:
= 2/6 = 1/3
Therefore, out of 3 probabilities the probability of getting two heads is 1.
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A coin has two sides head (H) and tail(T).
If we toss three coins then the possible outcomes are as follows:
(H,H,H) (H,H,T),(H,T,H),(T,H,H),(H,T,T),(T,H,T),(T,T,H) & (T,T,T)
SOLUTION:
Number of possible outcomes=8
{(H,H,H) (H,H,T),(H,T,H),(T,H,H),(H,T,T),(T,H,T),(T,T,H) & (T,T,T)}
Number of favourable outcomes (at least 2heads)=4
Probability (at least 2headd)= Number of favourable outcomes/total number of outcomes
Probability(P)(at least 2heads)= 4/8=½
P(at least 2 heads)= ½
Hence, the probability of getting at least 2 heads= ½.
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