Question

Three Coins are tossed simultaneously, find the probability to obtain -
1- Exact 3 heads.
2- At least two heads.
3- At least 2 tails.
4- No heads. ​

Answer 1

ANSWER:-

S = {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}

n(S) = 8

(1) Let A be the event of 3 heads

A = {HHH}

n(A) = 1

P(A) = n(A) /n(S) = 1/8

(2)Let B be the event of at least 2 heads

B = {HHH, HHT, HTH, THH}

n(B) = 4

P(B) = n(B)/n(S) = 4/8 = 1/2

(3) Let C be the event of at least 2 tails

C = {TTT, TTH, THT, HTT}

n(C) = 4

P(C) = n(C) /n(S) = 4/8 = 1/2

(4)Let D be the event of no heads

D = {TTT}

n(D) = 1

P(D) = n(D) /n(S) = 1/8

Hope it helps.

Answer 2

Answer:

same as above mate ..........