Question

three coins are tossed simultaneously.find the probability of getting i) at least one head ii) exactly two tails iii) at least two head​

Answer 1

Step-by-step explanation:

1. 1/12
2. 1/6
3. 1/6..........

Answer 2

Step-by-step explanation:

$if \: \: three \: \: coins \: \: are \: \: tossed$

$outcomes \: \: are \: \: (hht)(hhh)(htt)(hth)\\(thh)(ttt)(tth)(tht)$

$probability = \frac{favourable \: \: outcomes}{total \: \: no.of \: \: outcomes}$

$(i) \: \: probability = \frac{7}{8}$

$(ii) \: \: probability = \frac{3}{8}$

$(iii) \: \: \frac{5}{8}$

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