Math, asked by kumarniran61, 18 days ago


three coins are tossed simultaneously find the probablity of getting
(i) at least tail (ii) at most head (iii)all head

Answers

Answered by taniskhasoni3
1

Answer:

When three coins are tossed together, the total number of outcomes =8

i.e., (HHH,HHT,HTH,THH,TTH,THT,HTT,TTT)

Solution (i):

Let E be the event of getting exactly two heads

Therefore, no. of favorable events, n(E)=3(i.e.,HHT,HTH,THH)

We know that, P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

8

3

Solution (ii):

Let F be the event of getting atmost two heads

Therefore, no. of favorable events, n(E)=7(i.e.,HHT,HTH,TTT,THH,TTH,THT,HTT)

We know that, P(F) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

8

7

Solution (iii):

Let H be the event of getting at least one head and one tail

Therefore, no. of favorable events, n(H)=6(i.e.,HHT,HTH,THH,TTH,THT,HTT)

We know that, P(H) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

8

6

=

4

3

PLEASE MARK IT AS BRAINLIST

Step-by-step explanation:

When three coins are tossed together, the total number of outcomes =8

i.e., (HHH,HHT,HTH,THH,TTH,THT,HTT,TTT)

Solution (i):

Let E be the event of getting exactly two heads

Therefore, no. of favorable events, n(E)=3(i.e.,HHT,HTH,THH)

We know that, P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

8

3

Solution (ii):

Let F be the event of getting atmost two heads

Therefore, no. of favorable events, n(E)=7(i.e.,HHT,HTH,TTT,THH,TTH,THT,HTT)

We know that, P(F) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

8

7

Solution (iii):

Let H be the event of getting at least one head and one tail

Therefore, no. of favorable events, n(H)=6(i.e.,HHT,HTH,THH,TTH,THT,HTT)

We know that, P(H) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

8

6

=

4

3

PLEASE MARK IT AS BRAINLIST

PLEASE MARK IT AS BRAINLIST

Answered by faizakhan809sis
0

Step-by-step explanation:

Given: Three coins are tossed simultaneously.

When three coins are tossed then the outcome will be

TTT, THT, TTH, THH. HTT, HHT, HTH, HHH.

Hence total number of outcome is 8.

(i) For exactly two head we get favorable outcome as THH, HHT ,HTH

So, total number of favorable outcome i.e. exactly two head 3

We know that;

Probability =

N

u

m

b

e

r

o

f

f

a

v

o

r

a

b

l

e

e

v

e

n

t

T

o

t

a

l

n

u

m

b

e

r

o

f

e

v

e

n

t

Hence probability of getting exactly two head is

3

8

(ii) In case, at least two head we have favorable outcome as HHT, HTH, HHH ,THH

So, total number of favorable outcome i.e. at least two head is 4

We know that;

Probability =

N

u

m

b

e

r

o

f

f

a

v

o

r

a

b

l

e

e

v

e

n

t

T

o

t

a

l

n

u

m

b

e

r

o

f

e

v

e

n

t

Hence, probability of getting at least two head when three coins are tossed simultaneously is equal to

4

8

=

1

2

(iiii) At least one head and one tail we get in case THT, TTH, THH. HTT, HHT, HTH,

So, total number of favorable outcome i.e. at least one tail and one head is 6

We know that;

Probability =

N

u

m

b

e

r

o

f

f

a

v

o

r

a

b

l

e

e

v

e

n

t

T

o

t

a

l

n

u

m

b

e

r

o

f

e

v

e

n

t

Hence, probability of getting at least one head and one tail is equal to

6

8

=

3

4

(iv) No tail i.e HHH

Hence, total number of favorable outcome is 1

We know that;

Probability =

Number

o

f

f

a

v

o

r

a

b

l

e

e

v

e

n

t /

T

o

t

a

l

n

u

m

b

e

r

o

f

e

v

e

n

t

Hence, probability of getting no tails is

1

8

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