Question

Three coins are tossed simultaneously.
(i) S is the event of getting at least two heads.
(ii) A is the event if getting at least one tail (we have to find the probability..)​

Answer 1

Answer:

When three coins are tossed simultaneously, the possible outcomes are:

1. HHH
2. TTT
3. THT
4. HTH
5. TTH
6. HHT
7. HTT
8. THH

i.e. Total number of possible outcomes = 8

(i) Total number of possible outcomes= 8

   Number of favourable outcomes = 4

1. HHH
2. HTH
3. HHT
4. THH

   Therefore,

   P(S) = No. of favourable outcomes/ Total number of possible outcomes

          = 4/8

          = 1/2

(ii) Total number of possible outcomes = 8

    Number of favourable outcomes = 7

1. TTT
2. THT
3. HTH
4. TTH
5. HHT
6. HTT
7. THH

    Therefore,

    P(A) = No. of favourable outcomes/ Total number of possible outcomes

           = 7/8

Hence, Proved.