Three coins are tossed togerher. Find the PROBABILITY of getting (1) exactly two heads
(2) atleast two heads
(3) atmost two tails
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Step-by-step explanation:
Atleast 2 head = Exactly 2 heads + all 3 heads
All three heads is (1/2)*(1/2)*(1/2)=1/8
Exactly 2 heads = probability of 2 heads and 1 tail* the order they can show up
=(1/2)*(1/2)*(1/2)*3C2=3/8
Total probability=(1/8)+(3/8)=1/2
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