Question

Three coins are tossed together. Find the probability of
(i) exactly one tail
(ii) exactly two tails
(iii) at least one tail
(iv) at most two tails​

Answer 1

Answer:

When three coins are tossed together, the total number of outcomes =8

i.e., (HHH,HHT,HTH,THH,TTH,THT,HTT,

Solution (i):

Let E be the event of getting exactly two heads

Therefore, no. of favorable events, n(E)=3(i.e.,HHT,HTH,THH)

We know that, P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

3/8

Answer 2

Answer:

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