Question

Three coins are tossed what is the probability of getting at most two tails 43289 43108 43102 43107

Answer 1

Answer:

Step-by-step explanation:

Given that 3 coins are tossed,

let us assume that the coins are fair that means

probability of getting a head = probability of getting a tail

This follows a binomial distribution .

Let us assume that getting a tail as success let it be 'x'

Now, we need to find  P(x≤2)

In a binomial distribution with n trials and 'p' as probability of success

and 'q' as probability of failure,

P(X=r) is given by nCrp^rq^n-r

Now, n =3 p = 1/2 q =1/2

we need to find P(X≤2) which is equivalent to

1 - P(X=3)

P(x=3) = 3C3(1/2)^3

=1/8

Hence, P(X≤2) = 1-1/8

=7/8.

Hence, the probability of getting at most 2 tails is 7/8.

Answer 2

Answer: 7/8

Solution:

When three coins are tossed simultaneously than total outcomes are

TTT
TTH
THT
THH
HTT
HTH
HHT
HHH

Total outcomes = 8

Now favourable outcomes are :7

because in the condition of at most two tails we can not take 3 tails,and all remaining outcomes are favourable outcomes for the condition

So from basic probability conditions

Probability of getting at most 2 tails = 7/8

Hope it helps you