Question

three consecutive in integers are such that when they are taken in increasing order and multiplied by 3 4 and 5 respectively they add up to 386 . find this number ​

Answer 1

Step-by-step explanation:

Let the three consecutive integers be

(x), (x+1), (x+2)..........

(x) × 3 = 3x

(x+1) × 4 = 4x+4

(x+2)× 5 = 5x+10

Now we have to add these integers and the sum is 386.......

3x + 4x + 4 + 5x + 10= 386

12x + 14=386

12x = 372

x= 31

So the numbers are.........

31,32,33

hope it helps.........✌✌

Answer 2

Answer:

let three integers =x+1,x+2,x+3

ACCORDING TO THE QUESTION

3(x+1)+4(x+2)+5(x+3)=386

3x+3+4x+8+5x+15=386

3x+4x+5x=386-26

12x=360

x=360/12

x=30

The three integers are x+1=30+1=31

x+2=30+2=32

x+3=30+3=33

Hence the three integers are 30,31,32