Question

three consecutive integer are such that when they are taken in increasing order multiplied by 2,3 and 4 respectively,they add up to 74. find these number.​

Answer 1

Answer:

The numbers are 7 8 and 9

Step-by-step explanation:

Let the integers be x,x+1,x+2.

According to question

2x+3(x+1)+4(x+2)=74

2x+3x+3+4x+8=74

9x+11=74

9x=63

x=7

Therefore the numbers are 7,8 and 9

Answer 2

Step-by-step explanation:

Answer:Three consecutive integers are 7,8 and 9

Solution:

Let the numbers are x, x+1 and x+2

(Since these are consecutive integers)

they are taken in increasing order and multiplied by 2,3 and 4 respectively

So x becomes 2x

(x+1) becomes 3(x+1)

(x+2) becomes 4(x+2)

they add up to 74,so ATQ

2x + 3(x + 1) + 4(x + 2) = 74 \\ \\ 2x + 3x + 3 + 4x + 8 = 74 \\ \\ 9x + 11 = 74 \\ \\ 9x = 74 - 11 \\ \\ 9x = 63 \\ \\ x = \frac{63}{9} \\ \\ x = 7 \\ \\

So,

Integers are 7,8,9

Verification:

2 \times 7 + 3 \times 8 + 4 \times 9 \\ \\ = > 14 + 24 + 36 \\ \\ = >7 4 \\ \\

Hence the calculate integers are correct.

Hope it helps you