Math, asked by shahidibrahim19999, 1 year ago

three consecutive integer are such that when they are taken in ascending order and multiplyied by 2, 3 and 4 respectively they add up to 74. find the original no. s​

Answers

Answered by masoomptl
1

Answer:

7 , 8 & 9.

Step-by-step explanation:

Let these Three consecutive numbers are X, Y, and Z.

so Y = X+1, and Z = Y+1 = X+2

A/q,

        2X+3Y+4Z = 74

OR,  2X+3(X+1)+4(X+2) = 74

OR,  2X+3X+4X+3+8 = 74

OR,   9X = 74-11

OR,    X = 63/9 = 7

Therefore numbers are X = 7, Y = 7+1 = 8, and Z = 8+1 = 9

Answered by dhruv627
0

Answer:

Step-by-step explanation:

Let’s take the no. x,x+1,x+2

2x + 3x + 3 + 4x + 8 = 74

9x + 11 = 74

9x = 74 - 11

= 63

x = 63/9

= 7

So the answer is 7,8,9

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