Question

Three consecutive integers add up to 51.If they differ by 18,what are the numbers?​

Answer 1

Answer:

Let the numbers be x, x1, x2

Step-by-step explanation:

Therefore x+x1+x2=51

Thus the integers are 16,17 and 18.

As 16+17+18=51.

Answer 2

$\sf{\huge{\underline{\green{Given :-}}}}$

• Three consecutive integers add up to 51.If they differ by 18 .

$\sf{\huge{\underline{\green{To\:Find :-}}}}$

• The numbers.

$\sf{\huge{\underline{\green{Answer :-}}}}$

Let the three consecutive integers be ,

• First = x

• Second = ( x + 1 )

• Third = ( x + 2 )

They differ by 18 ,

• First = x - 18

• Second = ( x + 1 ) = x - 18 + 1 = x - 17

• Third = ( x + 2 ) = x - 18 + 2 = x - 16

x - 18 + x - 17 + x - 16 = 51

➝ 3x - 51 = 51

➝ 3x = 51 + 51

➝ 3x = 51 + 51

➝ 3x = 102

➝ x = 102 / 3

➝ x = 34

The three consecutive integers are ,

• First = x = 34

• Second = ( x + 1 ) = 35

• Third = ( x + 2 ) = 37

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