Question

Three consecutive integers add up to 51. The integers are..

1 point

A) 16,17,18

B) 14,15,16

C) 17,18,19

D) 15,16,17

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Answer 1

Answer:

Three consecutive integers

Let the first integer be x, second be (x+1) & third be (x+2)

x+x+1+x+2= 51

3x+3 = 51

3x= 51–3

3x = 48

x= 48/3

x = 16

3x = 48

x = 48/3

x = 16

x +1 = 16+1 =17

x+2 = 16+2 = 18

Hence the integers are 16,17 & 18

I Hope it helps

Answer 2

Answer:

Three consecutive integers

Let the first integer be x, second be (x+1) & third be (x+2)

x+x+1+x+2= 51

3x+3 = 51

3x= 51–3

3x = 48

x= 48/3

x = 16

3x = 48

x = 48/3

x = 16

x +1 = 16+1 =17

x+2 = 16+2 = 18

Hence the integers are 16,17 & 18