Question

Three consecutive integers add up to 51. What are these integers?​

Answer 1

Answer :-

• The three consecutive integers are 16, 17 and 18.

To find :-

• The three consecutive integers that add up to 51.

Solution :-

Let the first integer be "x".

Then :-

• The other two integers will be "x + 1" and "x + 2" as they are consecutive.

It is given that :-

• They add up to 51, which means that the sum of x, x + 1 and x + 2 is 51.

Therefore,

⟾ x + x + 1 + x + 2 = 51

⟾ 3x + 3 = 51

⟾ 3x = 51 - 3

⟾ 3x = 48

⟾ x = 48/3

⟾ x = 16

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Hence, the integers are :-

• x = 16.

• x + 1 = 16 + 1 = 17.

• x + 2 = 16 + 2 = 18$.$

Answer 2

Step-by-step explanation:

$let \: the \: 1st \: no. \: be \: x \: \\ the \: 2nd \: no. \: be \: x + 1 \\ the \: 3rd \: no. \: be \: x + 2 \\ \\ 1st \: no. + 2nd \: no. + \: 3rd \: no. \: = 51 \\ x + x + 1 + x + 2 = 51 \\ x + x + x + 1 + 2 = 51 \\ 3x + 3 = 51 \\ 3x = 51 - 3 \\ 3x = 48 \\ x = 48 \div 3 \\ x = 16 \\ \\ 1st \: integer \: x = 16 \\ 2nd \: integer \: x + 1 \\ = 16 + 1 \\ = 17 \\ 3rd \: integers \: x + 2 \\ = 16 + 2 \\ = 18 \\ \\ therefore \: the \: three \: consecutive \: integers \: are \: 16 \: 17 \: and \: 18$

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