three consecutive integers add up to 51. what are those integers
meenakshi997sa:
16...17..18
Answers
Answered by
4
Bonjour!!!
Let three consective numbers be x, x+1 and x+2
So, x + x + 1 + x + 2 = 51
≈> 3x + 3 = 51
≈> 3x = 48
≈> x = 48/3
x = 16
x + 1 = 17
x + 2 = 18
I hope this answer helped you.
Let three consective numbers be x, x+1 and x+2
So, x + x + 1 + x + 2 = 51
≈> 3x + 3 = 51
≈> 3x = 48
≈> x = 48/3
x = 16
x + 1 = 17
x + 2 = 18
I hope this answer helped you.
Answered by
2
Hii there!!!
Let the integers be = x , x + 1 and x + 2
According to the question,
the EQUATION formed=
x + x + 1 + x + 2 = 51
=> 3x + 3 = 51
=> 3x = 51 - 3
=> x = 48/3
=> x = 16
Therfore,
First integer = 16
Second integer = 17
Third integer = 18
Hope it helps dear.....
Let the integers be = x , x + 1 and x + 2
According to the question,
the EQUATION formed=
x + x + 1 + x + 2 = 51
=> 3x + 3 = 51
=> 3x = 51 - 3
=> x = 48/3
=> x = 16
Therfore,
First integer = 16
Second integer = 17
Third integer = 18
Hope it helps dear.....
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