Three consecutive integers add up to 51. What is the integers
Answers
Answered by
5
hii!!
here's ur answer...
let the three consecutive integers be x, x+1 and x+2
therefore x + x+1 + x+2 = 51
==> 3x + 3 = 51
==> 3x = 51 - 3
==> 3x = 48
==> x = 48/3
==> x = 16
hence, the three consecutive integers be are :-
x = 16
x + 1 = 16 + 1 = 17
x + 2 = 16 + 2 = 18
hope this helps..!!
here's ur answer...
let the three consecutive integers be x, x+1 and x+2
therefore x + x+1 + x+2 = 51
==> 3x + 3 = 51
==> 3x = 51 - 3
==> 3x = 48
==> x = 48/3
==> x = 16
hence, the three consecutive integers be are :-
x = 16
x + 1 = 16 + 1 = 17
x + 2 = 16 + 2 = 18
hope this helps..!!
Maharsh22:
a friendly explanation
Answered by
2
let the first number be n.
then
according to question
n+(n+1)+(n+2)=51
I.e
3n+3=51
3n=48
therefore n=16
n+1=17
n+2=18
so required numbers are :16 ,17and18
then
according to question
n+(n+1)+(n+2)=51
I.e
3n+3=51
3n=48
therefore n=16
n+1=17
n+2=18
so required numbers are :16 ,17and18
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