Question

Three Consecutive integers add up to 51. what is the
smallest no.


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Answer 1

Answer:

Let the first integer be x, second be (x+1) & third be (x+2)

x+x+1+x+2= 51

3x+3 = 51

3x= 51–3

3x = 48

x= 48/3

x = 16

3x = 48

x = 48/3

x = 16

x +1 = 16+1 =17

x+2 = 16+2 = 18

Hence the integers are 16,17 & 18

therefore the smallest integer is 16.

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Answer 2

Let the numbers be x, ( x+1 ) , (x+2)

A/q,

x + ( x+1 )+ (x+2) = 51

=> 3x + 3 = 51

=> 3x = 51-3

=> x = 48/3 = 16

Hence, the smallest number is 16