Question

three consecutive integers are are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively they add up to 74 find these numbers​

Answer 1

Answer:

Let the three consecutive integers be n,n+1,n+2 respectively.

According to the problem,

2n+3(n+1)+4(n+2)=74

or, 9n+11=74

or, 9n=63

or, n=7.

So the numbers are 7,8,9.

Answer 2

Answer:

7, 8, 9

Step-By-Step Explanation:

Let the three consecutive integers are x, x+1 and x+2.

According to the question,

2x + 3(x+1) + 4(x+2) = 74

⇒ 2x + 3x +3 + 4x + 8 = 74

⇒ 9x + 11 = 74

⇒ 9x = 74 – 11

⇒ 9x = 63

⇒ x = 63/9

⇒ x = 7

Thus, the numbers are:

x = 7

x + 1 = 8

x + 2 = 9