Question

three consecutive integers are arranged in ascending order and then multiplied by 5,4 and 6 respectively.These products add up to 226.Find the numbers

Answer 1

Let the consecutive integers be x, x + 1, x + 2


Ascending order = x, x +1, x + 2

Now first term is multiplied with 5, second with 4 and third with 6. The sum of their products is 226

=> 5(x) + 4(x + 1) + 6(x + 2) = 226

=> 5x + 4x + 4 + 6x + 12 = 226

=> 15x + 16 = 226

=> 15x = 226 - 16

=> 15x = 210

=> x = 210/15

=> x = 14


So first integer = 14

second = x + 1 = 15

third = x + 2 = 16


Hope it helps dear friend ☺️

Answer 2

Step-by-step explanation:

let consecutive integers be x, x+1 ,x+2

First with =5

Second with=4

Third with = 6

Sum of the product=226

5x+4(x+1) +6(x+2) =226

5x+4x+4 +6x+12 =226

15x+16. =226

15x. =226-16= 210

x. 210/15

x . = 14

First integer = x=14

second integer = x +1=15

Third integer = x +2 = 16

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Behind the scence

14+1=15

14+2=16