three consecutive Integers are as such whenthey are taken in increasing order and multiplied by 2,3,4 respectively,they add upto 56.find these numbers
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Let the first number be X.
:. Second Number=x+1
& Third number=x+2
ATQ-
2x+3(x+1)+4(x+2)=56
2x+3x+3+4x+8=56
9x+11=56
9x=56-11
9x=45
X=45/9
X=5 (First number)
:. x+1=5+1=6 (Second Number)
& X+2=5+2=7 (Third Number)
ÆÑẞWĒRẞ)
#Mãrk åß thē Brāìñlïêßt
Rëgàrdß
Tèám Kâñçhä
:. Second Number=x+1
& Third number=x+2
ATQ-
2x+3(x+1)+4(x+2)=56
2x+3x+3+4x+8=56
9x+11=56
9x=56-11
9x=45
X=45/9
X=5 (First number)
:. x+1=5+1=6 (Second Number)
& X+2=5+2=7 (Third Number)
ÆÑẞWĒRẞ)
#Mãrk åß thē Brāìñlïêßt
Rëgàrdß
Tèám Kâñçhä
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