three consecutive integers are such that taken in increasing orderand multiplied by 2,3 and 4 respectively,they add up to 74.Find these numbers
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Let the number be x,x+1,x+2
2x+3(x+1) + 4 (x+2)=74
2x+3x+3+4x+8=74
9x+11=74
9x=74-11
9x=63
x=63/9
x=7
therefore the number is 7, 8 ,9
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2x+3(x+1) + 4 (x+2)=74
2x+3x+3+4x+8=74
9x+11=74
9x=74-11
9x=63
x=63/9
x=7
therefore the number is 7, 8 ,9
thank q follow me
Answered by
3
Answer:
Question:- three consecutive integers are such that taken in increasing orderand multiplied by 2,3 and 4 respectively,they add up to 74.Find these numbers.
Answer:- let the three consecutive intergers be x,x+1,x+2
=2x+3(x+1)+4(x+2)=74
=2x+3x+3+4x+8=74
=2x+3x+4x+3+8=74
=9x+11=74
=9x+74-11
=9x=63
=x=63 7
9 1
The consecutive number 7,8,9
hope it will help you:-)
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