three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3,4they add up to 74.Find these numbers
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let the numbers be p, p+1, p+2.
p x 2 = 2p
p+1 x 3 = 3p + 3
p+2 x 4 = 4p+8
adding
2p+3p+3+4p+8 = 74
9p+ 11 = 74
9p = 63
p=7
nos are 7,8,9
p x 2 = 2p
p+1 x 3 = 3p + 3
p+2 x 4 = 4p+8
adding
2p+3p+3+4p+8 = 74
9p+ 11 = 74
9p = 63
p=7
nos are 7,8,9
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