three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3 and 4 respectively, they add up to 74.find these numbers
Answers
Answered by
314
let the three consicutive integer are x,x+1,x+2
according to the question
2x+3(x+1)+4(x+2)=74
2x+3x+3+4x+8=74
9x+11=74
9x=74-11
9x =63
x=63/9
x=7
then
the first integer=7
second integer=7+1=9
third integer =7+2=9
plzzz mark as brain list answer
according to the question
2x+3(x+1)+4(x+2)=74
2x+3x+3+4x+8=74
9x+11=74
9x=74-11
9x =63
x=63/9
x=7
then
the first integer=7
second integer=7+1=9
third integer =7+2=9
plzzz mark as brain list answer
Answered by
211
let the three integers be x, x+1, x+2
then according to the question
2x + 3(x +1) + 4 (x+2) = 74
2x + 3x + 3 + 4x + 8 = 74
9x + 11 = 74
9x = 74 - 11
9x = 63
x = 63 ÷ 9
x = 7
so the first integer = 7
second integer(x+1) = 7+1
= 8
third integer(x+2) = 7+2
= 9
hope this helps plz mark as brainelist
then according to the question
2x + 3(x +1) + 4 (x+2) = 74
2x + 3x + 3 + 4x + 8 = 74
9x + 11 = 74
9x = 74 - 11
9x = 63
x = 63 ÷ 9
x = 7
so the first integer = 7
second integer(x+1) = 7+1
= 8
third integer(x+2) = 7+2
= 9
hope this helps plz mark as brainelist
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