Question

three consecutive integers are such that when they are taken in increasing order and multiplied by 2 3 and 4 respectively they added upto 74 find these numbers​

Answer 1

Answer:

answer is X=7

Step-by-step explanation:

2(X)+3(X+1)+4(X+2)=74

2X+3X+3+4X+8=74

9X+11=74

9X=74-11

9X=63

X=63/9

X=7

the first number=2X=2(7)=14

the second number=3X+3=3(7)+3=21+3=24

the third number=4X+8=4(7)+8=28+8=36

14+24+36=74

38+36=74

74=74

So, hence it is proved