Three consecutive integers are such that when they are taken in increating order and multiplied by 3,4 and 5 respectively,they add up to 386 . find these numbers.
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31,32,33
Step-by-step explanation:
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Answer:
31, 32 and 33
Step-by-step explanation:
Let the first number be x
So the other two numbers will be (x+1)(x+2)
For example: If you have the first number as 2 the other two number will be 2+1=3 and 2+2=4.
So now according to the question
The first number is multiplied by 3, second by 4 and third by 5 and then if they are added the sum will be 386
Now we will write the equation
3×x + 4×(x+1) + 5× (x+2) = 386
3x + 4x + 4 + 5x + 10 = 386
12x+14 = 386
12x=372
x=372/12
x=31
Therefore the first number is 31
Second number is 32
Third number is 33
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