Math, asked by arpita83p, 9 months ago

Three consecutive integers are such that when they are taken in increating order and multiplied by 3,4 and 5 respectively,they add up to 386 . find these numbers.

Answers

Answered by abc41444144
0

31,32,33

Step-by-step explanation:

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Answered by Anonymous
2

Answer:

31, 32 and 33

Step-by-step explanation:

Let the first number be x

So the other two numbers will be (x+1)(x+2)

For example: If you have the first number as 2 the other two number will be 2+1=3 and 2+2=4.

So now according to the question

The first number is multiplied by 3, second by 4 and third by 5 and then if they are added the sum will be 386

Now we will write the equation

3×x + 4×(x+1) + 5× (x+2) = 386

3x + 4x + 4 + 5x + 10 = 386

12x+14 = 386

12x=372

x=372/12

x=31

Therefore the first number is 31

Second number is 32

Third number is 33

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