Question

Three consecutive integers are such that when they are taken in increasing order and
multiplied by 2,3 and 4 respectively, they add up to 74. Find these numbers.​

Answer 1

Answer:

let the inetgers =(x),(x+1),(x+2)

then multiple this integer with 2,3,4=2(x),3(x+1),(4x+2)

We get=(2x),(3x+3),(4x+8)

according to question

2x+3x+3+4x+8=74

9x+11=74

9x=74-11

9x=63

x=63÷9

x=7

the inetgers is( 7, )(7+1),(7+2)=7,8,9

Answer 2

Answer:

7, 8, 9

Step-By-Step Explanation:

Let the three consecutive integers are x, x+1 and x+2.

According to the question,

2x + 3(x+1) + 4(x+2) = 74

⇒ 2x + 3x +3 + 4x + 8 = 74

⇒ 9x + 11 = 74

⇒ 9x = 74 – 11

⇒ 9x = 63

⇒ x = 63/9

⇒ x = 7

Thus, the numbers are:

x = 7

x + 1 = 8

x + 2 = 9