Three consecutive integers are such that when they are taken in increasing order and are multiplied by 2,3,4 respectively, they add up to 92. Find the numbers.
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Let the three consecutive integers be x, x+1 and x+2.
according to question
2(x) + 3(x+1) + 4(x+2) = 92
2x+3x+3+4x+8=92
9x+11=92
9x=92-11
9x=81
x=81/9
x=9
The three numbers are
x= 9
x+1=10
x+2=11
according to question
2(x) + 3(x+1) + 4(x+2) = 92
2x+3x+3+4x+8=92
9x+11=92
9x=92-11
9x=81
x=81/9
x=9
The three numbers are
x= 9
x+1=10
x+2=11
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