Three consecutive integers are such that when they are taken in increasing order and
multiplied by 3, 4 and 5 respectively, they add up to 182. Find these numbers.
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Answers
Answered by
1
Answer:
These numbers are 14, 15 and 16
Step-by-step explanation:
Let the integers be x,x+1 and x+2
According to question
3(x) + 4(x+1) + 5(x+2) = 182
3x + 4x + 4 + 5x + 10 = 182
12x + 14 = 182
12x = 182 - 14 = 168
x = 168/12
x = 14
x+1 = 14 + 1 = 15
x+2 = 14 + 2 = 16
Answered by
0
Step-by-step explanation:
let the numbers be x, x+,1, x+2
atq.
(x)3 + (x+1)4 + (x+2)5 = 182
3x + 4x + 4 + 5x+ 10 = 182
12x + 14 = 182
12x = 182-14
x = 168÷12
x = 14 ans.
therefore, the numbers are:
(x)3 = 14×3= 42 ans!
(x+1)4 =15×4=60 ans!
(x+2)5 =16×5=80 ans!
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