three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 they add up to 74 find these numbers
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Let the First Number be x
∴ As per Question
2x + 3x+3 + 4x + 8 = 74
9x + 11 = 74
9x = 63
x = 63/9
x = 7
First Number=x=7
Second Number=x+1=8
Third Number=x+2=9
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