Question

three consecutive integers are such that when they are taken in increasing order and multiplied by 3, 4 and 5 respectively added up to 386. find these numbers.

Answer 1

Let the consecutive integers be=x,x+1,x+2

1st integer is mutliplied by 3.

2nd integer is multiplied by 4.

3rd integer is multiplied by 5.

So,the equation will be something like this-

3(x)+4(x+1)+5(x+2)=386.

=3x+4x+4+5x+10=386.

12x+14=386.

12x=386-14.

12x=372.

x=372/12.

x=31.

Therefore,

1st integer=3x--->3*31=93.

2nd integer=4x+4---->4*31+4=128.

3rd integer=5x+10---->5x+10=5*31+10----->165.

Hope that this helps you!

-TGA.