Math, asked by Daniya34, 11 months ago

three consecutive integers are such that when they are taken increasing order and multiplied by 3 ,4 and 5 respectively. They add up to 386.find these numbers
fast
i wll mrk thm as brailiest!!!

Answers

Answered by DevanshP
1

Answer:

the numbers are 31,32,33

Step-by-step explanation:

let the first number = x

three consecutive numbers = x, x+1, x+2

x*3+4(x+1)+5(x+2)=386

3x+4x+5x+4+10=386

12x=386-14

x=372/12

x=31

x+1=31+1=32

x+2=31+2=33

Answered by aaditya782005
1
let the integers be x,x+1,x+2
A.T.c.
3(x)+ 4(x+1)+5(x+2) =386
3x+4x+4+5x+10=386
12x+14=386
12x=386-14
12x=372
x=372/12
x=31
integers are 31,32,33
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