three consecutive integers are such that when they are taken increasing order and multiplied by 3 ,4 and 5 respectively. They add up to 386.find these numbers
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Answers
Answered by
1
Answer:
the numbers are 31,32,33
Step-by-step explanation:
let the first number = x
three consecutive numbers = x, x+1, x+2
x*3+4(x+1)+5(x+2)=386
3x+4x+5x+4+10=386
12x=386-14
x=372/12
x=31
x+1=31+1=32
x+2=31+2=33
Answered by
1
let the integers be x,x+1,x+2
A.T.c.
3(x)+ 4(x+1)+5(x+2) =386
3x+4x+4+5x+10=386
12x+14=386
12x=386-14
12x=372
x=372/12
x=31
integers are 31,32,33
A.T.c.
3(x)+ 4(x+1)+5(x+2) =386
3x+4x+4+5x+10=386
12x+14=386
12x=386-14
12x=372
x=372/12
x=31
integers are 31,32,33
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