Question

Three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3and 4respectively they add up to 74​

Answer 1

Three consecutive integers

=x, x+1, x+2

According to question

(x*2)+[(x+1)*3]+[(x+2)*4]=74

Explanation-

first integer = x which is multiplied into 2

= x*2

second integer = x+1 which is multiplied by 3

= (x+1)*3

Third integer = x+2 multiplied by 4

= (x+2)*4

Add 'em up. We get-

(x*2)+[(x+1)*3]+[(x+2)*4]=74

Simplify it up

2x+3x+3+4x+8=74

9x+11=74

9x= 63

x=63/9

x=7

Thus,

first integer= x= 7

Second = x+1 = 8

Third = x+2 =9

Please mark this as Brainliest if you like my Answer....