Question

three consecutive integers are such when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 56 find these numbers. please explain it properly.....​

Answer 1

Let the three consecutive integers be x, x+1, x+2 in increasing order

Multiply 2,3,4 respectively

2(x)+3(x+1)+4(x+2)

This aad up to 74

2(x)+3(x+1)+4(x+2)=74

2x+3x+3+4x+8=74

9x+11=74

9x=74-11=63

X=63÷9=7

Therefore the three consecutive integers are 7,8,9

Answer 2

Answer:

Let the consecutive integers be x, x+1,x+2 ( eqn 1)

According to question

Step-by-step explanation:

2x+3(x-1)+4(x+2)=74

=> 2x +3x+3+4x+8=74

=> 9x+11=74

=> 9x=74-11

=> 9x=63

=> x=63/9

x=7

Put the value of x in eqn 1

X=7, x+1=8 ,x+2=9