Three consecutive integers such that when they are taken in increasing order and X 2 3 and 4 respectively they add up to 74 find these numbers
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let three consecutive no. are X, Y , Z
then
Y = X+1 and Z = Y+1 = X + 2
a/q
2X+3Y+4Z = 74
or , 2x + 3(x+1) +4(x+2)
9x = 74-11
× = 63/9
x= 7
therefore no. are X = 7
Y = 7+1=8
Z = 8 +1 = 9
then
Y = X+1 and Z = Y+1 = X + 2
a/q
2X+3Y+4Z = 74
or , 2x + 3(x+1) +4(x+2)
9x = 74-11
× = 63/9
x= 7
therefore no. are X = 7
Y = 7+1=8
Z = 8 +1 = 9
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