Three consecutive it is are such that when they are taken increasing order and multiplied by 2 3 and 4 respectively they are upto 70 find these number
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1st number is = x
2nd number is =x-1
3rd number is =x-2
then multiplied
1st number=2x
2nd number=3(x-1)=3x-3
3rd number = 4(x-2)=4x-8
2x+3x-3+4x-8=70
9x-11 =70
; ; 9x=70+11
x=81/9
x=9
1st number is=x=9
2nd number is=x-1=9-1=8
3rd number is =x-2=9-2=7
2nd number is =x-1
3rd number is =x-2
then multiplied
1st number=2x
2nd number=3(x-1)=3x-3
3rd number = 4(x-2)=4x-8
2x+3x-3+4x-8=70
9x-11 =70
; ; 9x=70+11
x=81/9
x=9
1st number is=x=9
2nd number is=x-1=9-1=8
3rd number is =x-2=9-2=7
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