Question

Three consecutive multiples of seven such as the sun as 4 times the third exceeded 3 times the second by 133

Answer 1

Given:

3 consecutive multiples of 7

4 times the third exceed the second by 133

To Find:

The 3 numbers

Solution

Define x:

Let the numbers be x - 7 , x , x + 7

Solve x:

4 times the third exceed the second by 133

4(x + 7) -x = 133

4x + 28 - x = 133

3x + 28 = 133

3x = 105

x = 35

Find the numbers:

x - 7 = 35 - 7

x - 7 = 28

x = 35

x + 7 = 35 + 7

x + 7 = 42

Answer: The numbers are 28. 35 and 42

Answer 2

Answer:

the numbers are 28.35 and 42