Question

Three consecutive numbers are such that when taken in increasing order and multipied by 2 3 and 4 respectively the add up to 74. Find the numbers

Answer 1

↑ Here is your answer ↓ _____________________________________________________________ _____________________________________________________________

Let those numbers be

$x, x+1, x+2$

Given that

$2x + 3(x+1) + 4(x+2) = 74$

$2x + 3x+3+4x+8 = 74$

$9x + 11 = 74$

$9x = 63$

$x= 63/9$

$x = 7$

So, the numbers are

$x = 7$

$x+1 = 8$

$x+2 = 9$

Answer 2

Let the Numbers are,

• x
• x + 1
• x + 2

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When taken in increasing order,

x, (x +1), (x + 2)

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According to the given information,

2(x) + 3(x+1) + 4(x +2) = 74

=> 2x + 3x + 3 + 4x + 8 = 74

=> 2x + 3x + 4x + 8 + 3 = 74

=> 9x + 11 = 74

=> 9x = 74-11

=> 9x = 63

=> x = 63/9

=> x = 7

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Numbers are
• x = 7
• x +1 = 7 +1 = 8
• x +2 = 7+2=9



I hope this will help you

-by ABHAY