Three consecutive odd integers are in increasing order such that the sum of the last two integers is 13 more than the first integer. find the three integers?
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Let the smallest number be x
so other numbers are x + 2 & x + 4
so by the condition given in your question we get equation
x + 13 = x + 2 + x + 4
x + 13 = 2x + 6
2x - x = 14 - 6
x = 7
so the numbers are 7 , 9 & 11
so other numbers are x + 2 & x + 4
so by the condition given in your question we get equation
x + 13 = x + 2 + x + 4
x + 13 = 2x + 6
2x - x = 14 - 6
x = 7
so the numbers are 7 , 9 & 11
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