Question

three consecutive odd integers are such that if the largest is subtracted from twice their sum,the result is 93,then the smallest integer is
(i)17 (ii)18 (iii)19 (iv)20
please write in simple language I am in 7 grade​​

Answer 1

Step-by-step explanation:

Let the numbers be x, x+1, x+2.

Answer 2

Answer:

Let three consecutive numbers be

x-2,x,x+2

Their sum= x-2+x+x+2=3x

Twice their sum=2×3x=6x

By condition,6x-(x+2)=93

or,6x-x-2=93

or,5x=93+2

or,x=95/5=19

Therefore, the smallest odd number is x-2

= 19-2

=17 (Ans)