three consecutive odd integers are taken in increasing order.
3 times is smallest odd number decreased by 7 equal to twice the largest one. find the numbers
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let the 3 odd no.s be as
x,x+2,x+4.
according to the condition,
3x-7=2(x+4)
3x-7=2x+8
3x-2x=7+8
x=15
therefore the no.s are 15,17and19
x,x+2,x+4.
according to the condition,
3x-7=2(x+4)
3x-7=2x+8
3x-2x=7+8
x=15
therefore the no.s are 15,17and19
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