Question

three consecutive terms of an ap whose sum is -3 and their product of their cube is 512​

Answer 1

Step-by-step explanation:

Let the numbers be (a−d),a,(a+d). Then,

Sum=−3⇒(a−d)+a+(a+d)=−3⇒3a=−3⇒a=−1

Product of their cubes=512⇒(a−d)

3

×a

3

×(a+d)

3

=512

⇒(a

2

−d

2

)

3

×a

3

=512

⇒−(1−d

2

)

3

=512 (∵a=−1)

⇒−(1−d

2

)=8

⇒d

2

=9⇒d=±3

If d=3, then the numbers are −4,−1,2. If d=−3, then the numbers are 2,−1,−4.