Question

Three consecutive whole numbers are such that if they be divided by 5, 3 and 4 respectively; the sum of the quotients is 40. Find the numbers.

Answer 1

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Answer 2

x/5 + x+1/5 + x+2/5 = 40-----------------> 12x+20x+15x+20+30=2400

47x + 50 = 2400------> x = 2350/47

x=50, x+1=51, x+2=52.