Question

Three containers a, b and c have volumes a, b, and c respectively; and container a is full of water while the other two are empty. if from container a water is poured into container b which becomes 1/3 full, and into container c which becomes 1/2 full, how much water is left in container a?'

Answer 1

total water in b and c container=b/3 + c/2
now,
Water in a container is= a-(b/3 + c/2)
Ans is- (6a-2b+3c)/6

Answer 2

Given :

The volume of container a = a cubic unit

The volume of container b = b cubic unit

The volume of container b = b cubic unit

To Find :

Quantity of water left in container a

Solution :

The container a is poured full with water

As The volume of container a = a cubic unit

So, The quantity of water in container a = a cubic unit

Now,

$\dfrac{1}{3}$ rd of water from container a poured into container b

And $\dfrac{1}{2}$ of water from container a poured into container c

So, Total quantity of water in both b and c  container =  $\dfrac{b}{3}$  + $\dfrac{c}{2}$

                                                                                         = $\dfrac{2b+ 3c}{6}$

Now, Quantity of water left in container a = initial quantity of water in a - sum of quantity of water removed

So,  Quantity of water left in container a = a - ( $\dfrac{2b+ 3c}{6}$ )

                                                                  = $\dfrac{6 a -2b - 3c}{6}$

Hence, The Quantity of water left in container a is  $\dfrac{6 a -2b - 3c}{6}$ Answer