Question

three cube of side n is placed one over then the total surface area of the resultant solid is.....................​

Answer 1

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Hope you understood the answer

Answer 2

The resultant solid is a cuboid

Side of cube = n

Therefore, length of cuboid (l)= 3n

Breadth of cuboid (b) = n

Height of cuboid (h)= n

Total Surface Area = 2(lb + bh + hl)

=2(3n×n + n×n + n×3n)

=2(3n^2 + n^2 + 3n^2)

=2(7n^2)

=14n^2 sq. units

Hope it helps.....

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