Three cubes each of side 5cm are joined end to end. Find the surface area of resulting cubiod
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Height of the cuboid = 5cm
Length = 5+5+5=15cm
Breadth = 5cm
Surface area = 2*(lb)+(bh)+(lh)
= 2*(15*5)+(5*5)+(15*5)
= 2*(75+25+75)
= 2*175
= 350cm^2.
Therefore, the surface area of the cuboid formed by joining three cubes of side 3 cm is 350cm^2.
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Length = 5+5+5=15cm
Breadth = 5cm
Surface area = 2*(lb)+(bh)+(lh)
= 2*(15*5)+(5*5)+(15*5)
= 2*(75+25+75)
= 2*175
= 350cm^2.
Therefore, the surface area of the cuboid formed by joining three cubes of side 3 cm is 350cm^2.
Please mark as brainliest if it helps you.....
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6
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