Question

Three cubes each of the volume 64 cm cube are joining end to end the surface area of the resulting cuboid is

Answer 1

$\huge \underline \mathsf \red {AnsWer:-}$

Given:

• The Volume (V) of each cube is = 64 cm³.

This implies that a³ = 64 cm³

Therefore, a = 4 cm

Now,

• The side of the cube = a = 4 cm

Also, the length and breadth of the resulting cuboid will be 4 cm each. While its height will be 8 cm.

So, the surface area of the cuboid = 2(lb + bh + lh)

= 2(8×4 + 4×4 + 4×8) cm²

= 2(32 + 16 + 32) cm²

= (2 × 80) cm²

= 160 cm²

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$

Answer 2

${ \huge{ \boxed {\boxed{ \tt { \color{red}{answer}}}}}}$

The Volume (V) of each cube is = 64 cm^3

This implies that a3 = 64 cm^3

∴ The side of the cube, i.e. a = 4 cm

Also, the breadth and length of the resulting cuboid will be 4 cm each while its height will be 8 cm.

So, the surface area of the cuboid (TSA) = 2(lb + bh + lh)

Now, by putting the values, we get,

= 2(8×4 + 4×4 + 4×8) cm^2

= (2 × 80) cm√2

Hence, TSA of the cuboid = 160 cm^2

Hope it's Helpful.....:)