three cubes of 10 cm each are joined end to end to make a cuboid. find the surface area of resulting solid
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Length of the cuboid = 3x10 = 30cm
Breadth of the cuboid = 10cm
Height of cuboid = 10cm
TSA=2(lb+bh+hl)
= 2(30x10+10x10+30x10)
= 2(300+100+300)
=2(700)
=1400cm2
Breadth of the cuboid = 10cm
Height of cuboid = 10cm
TSA=2(lb+bh+hl)
= 2(30x10+10x10+30x10)
= 2(300+100+300)
=2(700)
=1400cm2
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Answered by
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HEYA...!!!!
Your answer is......
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Given , side of a cube =10 cm
Side of a cubiod if 3 cubes are joined together =30cm=length
Height =10cm
Breadth =10cm
Surface area of cubiod =2(lb+bh+lh)
=>2(30*10+10*10+30*10)
=>2(300+100+300)
=>2(700)
=>1400cm^2
❇️HOPE IT HELPS .....☺
Your answer is......
----------------------------------------------
----------------------------------------------
Given , side of a cube =10 cm
Side of a cubiod if 3 cubes are joined together =30cm=length
Height =10cm
Breadth =10cm
Surface area of cubiod =2(lb+bh+lh)
=>2(30*10+10*10+30*10)
=>2(300+100+300)
=>2(700)
=>1400cm^2
❇️HOPE IT HELPS .....☺
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