Question

Three cubes of iron whose edges are 6cm, 8cm and 10 cm respectively are melted and formed into a single cube. The edge of the new cube formed is :

Answer 1

volume of cube 1=a1^3= 6×6×6 =216cm^3
volume of cube2= a2^3= 8×8×8= 512cm^3
volume of cube3=a2^3=10×10×10=1000cm^3

volume of new cube = volume of cube1+volume of cube2+volume of cube3
a^3= 216+512+1000=1728cm^3
a=12

therefore edge of new cube is 12cm.
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Answer 2

Answer:12 cm

Step-by-step explanation:

volume of a sphere - 4/3 * 22/7 * r^3

sum of volume of all sphere = volume of resulting sphere

sum of all volumes - 4/3*22/7(6^3+8^3+10^3)

=4/3×22/7×1728

this is the volume of resulting sphere but we know the formula is 4/3*22/7*r^3

4/3*22/7*1728=4/3*22/7*r^3

r^3 = 1728

r = 12 cm