Three cubes of iron whose edges are 6cm, 8cm and 10 cm respectively are melted and formed into a single cube. The edge of the new cube formed is :
Answers
Answered by
2
volume of cube 1=a1^3= 6×6×6 =216cm^3
volume of cube2= a2^3= 8×8×8= 512cm^3
volume of cube3=a2^3=10×10×10=1000cm^3
volume of new cube = volume of cube1+volume of cube2+volume of cube3
a^3= 216+512+1000=1728cm^3
a=12
therefore edge of new cube is 12cm.
hope it helps you.
please mark it as brainliest.
volume of cube2= a2^3= 8×8×8= 512cm^3
volume of cube3=a2^3=10×10×10=1000cm^3
volume of new cube = volume of cube1+volume of cube2+volume of cube3
a^3= 216+512+1000=1728cm^3
a=12
therefore edge of new cube is 12cm.
hope it helps you.
please mark it as brainliest.
Answered by
2
Answer:12 cm
Step-by-step explanation:
volume of a sphere - 4/3 * 22/7 * r^3
sum of volume of all sphere = volume of resulting sphere
sum of all volumes - 4/3*22/7(6^3+8^3+10^3)
=4/3×22/7×1728
this is the volume of resulting sphere but we know the formula is 4/3*22/7*r^3
4/3*22/7*1728=4/3*22/7*r^3
r^3 = 1728
r = 12 cm
Similar questions