three cubes of iron whose edges are 6cm,8cm,and 10cm are melted and formed into a single cube.The edge of the new cube formed is_
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Volume of the cube having edge 6cm=V₁=6³= 216cm³
Volume of the cube having edge 8cm=V₂=8³= 512cm³
Volume of the cube having edge 10cm=V₃=10³= 1000cm³
Total volume
= V₁+V₂+V₃
=216+512+1000
=1728 cm³
Volume of the new cube= 1728 cm³
Edge of the new cube= (1728)¹/³=12 cm Ans.
Volume of the cube having edge 8cm=V₂=8³= 512cm³
Volume of the cube having edge 10cm=V₃=10³= 1000cm³
Total volume
= V₁+V₂+V₃
=216+512+1000
=1728 cm³
Volume of the new cube= 1728 cm³
Edge of the new cube= (1728)¹/³=12 cm Ans.
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